Question

I need to find the total and net ionic equations for the following reactions:

Thank you so extremely much in advance.

HCl (aq) + Al (s)

Fe(s) + HCl (aq)

Mg(s) + HCl (aq)

Zn(s) + HCl (aq)

Fe (s) + H2SO4 (aq)

Mg (s) + H2SO4 (aq)

Zn(s) + H2SO4 (aq)

Copper II Nitrate (aq) + Zinc(s)

Answer 1

1) First let us write the balanced equation

      2Al (s) + 6HCl (aq) ----> 3H2(g) + 2 AlCl3(aq)

     If we are separated all campounds into ions then that will be the ionic equation

     2Al (s) + 6H+ + 6Cl- (aq) ----> 3H2(g) + 2 Al³⁺ + 6Cl^-(aq)

     If cancelled Cl-, which is both sides, we will get net ionic equation

     2Al (s) + 6H+ (aq)  ----> 3H2(g) + 2 Al³⁺(aq)

Similarly if workedout for other equations we will get as below

2) Fe(s) + 2HCl (aq) ----> FeCl2(aq) + H2(g) ....Balanced equation

    Fe(s) + 2H+ (aq) ----> Fe²⁺(aq) + H2(g).....Net ionic equation

3) Mg(s) + 2H+ (aq) ----> Mg²⁺(aq) + H2(g).....Net ionic equation

4) Zn(s) + 2H+ (aq) ----> Zn²⁺(aq) + H2(g).....Net ionic equation

5) Fe(s) + 2H+ (aq) ----> Fe²⁺(aq) + H2(g).....Net ionic equation

6) Mg(s) + 2H+ (aq) ----> Mg²⁺(aq) + H2(g).....Net ionic equation

7) Zn(s) + 2H+ (aq) ----> Zn²⁺(aq) + H2(g).....Net ionic equation

8) Zn(s) + Cu2+ (aq) ----> Zn²⁺(aq) + Cu(s).....Net ionic equation