In: Statistics and Probability
In a semiconductor manufacturing process, 3 wafers from a lot are tested. Each wafer is classified as pass or fail (binomial). Assume that the probability that a wafer passes the test is 0.7 and that the wafers are independent.
a. Fill in the table. Round answers to three decimal places (i.e. 0.123)
X Wafers Pass |
P(X) |
X*P(X) |
(x-mu)2*P(X) |
0 |
0.027 |
0 |
________Answer |
1 |
_______Answer |
_________ Answer |
0.229 |
2 |
0.441 |
0.882 |
0.004 |
3 |
______Answer |
1.029 |
0.278 |
b. What is the mean? Round answer to one decimal place (i.e. 1.2) Answer
c. What is the standard deviation? Round answer to three decimal places (i.e. 0.123)Answer
d. What is the probability of X > 1? Round answer to three decimal places
it is a binomial probability distribution,
because
there is fixed number of trials,
only two outcomes are there, success and
failure
trails are independent of each other
and probability is given by
P(X=x) = C(n,x)*px*(1-p)(n-x) |
where
Sample size , n = 3
Probability of an event of interest, p = 0.7
a)
X | P(X) | X*P(X) | (X-mean)² * P(X) | ||
0 | 0.027 | 0.000 | 0.119 | ||
1 | 0.189 | 0.189 | 0.229 | ||
2 | 0.441 | 0.882 | 0.004 | ||
3 | 0.343 | 1.029 | 0.278 |
b)
mean = E[X] = Σx*P(X) = 2.1
c)
variance=Σ(X-mean)² * P(X) = 0.63
std dev = √variance = √0.63 = 0.794
d)
P(X>1) = P(X=2) + P(X=3) = 0.189+0.343 = 0.784