In: Physics
(e) Consider approximately 1024 gas molecules in a box. A divider which can conduct heat, for example a rubber diaphragm, separates the box into two chambers of equal size. Each chamber contains half of the molecules. Assume that the internal energy of the gas is (approximately) fixed.
Each partition contains 512 particles
The internal energy is fixed
the V of both the boxes is same,
as only energy exchange is possible, it is a canonical ensemble
Imagine all the gas molecules in the room you are sitting in. Now in your mind divide the room into two sides (left and right). Each molecule carrying some amount of energy could be anywhere in that room. Each molecule has a an equal chance of being either on the left side or the right side of the room. The odds that all of the molecules are on the right side of the room are very very jsmall. The odds that the molecules are essentially evenly distributed between both sides of the room are astronomically large. This is the essence of the microscopic view of entropy.
Quantitatively the entropy is given as
where, S is the entropy and is the number of microstates and k is just a constant
There are fewer ways to arrange the molecules and have them all on one side. Fewer microstates means low entropy. There are more ways to arrange the molecules and have them evenly distributed, therefore more microstate means more entropy.
so more evenly distributed equates to more entropy.
The entropy of the gas is highest when the energy is evenly spread among the molecules and the molecules are evenly spread in the volume.
The number of microstates in the two boxes is a product
and hence entropies of two independent systems is additive
this can be used to find possible macrostates of the system.
A low entropy macrostate would be the one where all the energy is concentrated and all the molecules are concentrated in a small volume.