Question

In this experiment, the mass hanger is placed at an height of 50cm
from the ground holding a mass of 100g. When the hanger is released ,
it moves with a velocity of 1 m/s. Verify the principle of conservation of mechanical energy.
Mass of the disk= 991g radius of the disk=12.7cm

Answer 1

From the problem we have to found out the conservation of mechanical energy of the disc.Hence we take three positions to prove it,by mistake I uploaded the previous picture,But this is the correct

50 ano na 1st case: When the disk was placed at the top nie a, position, the more total mechanical energy was its potential energy E = Ttv = nigh as T=0] =69691 € + 0,100) * 10x150 Igalomis2 f = 545 N = 5.45N adourning 7 and case : Now at the position when we treated the disc at ae the total mechanical energy will be the sum of kinetic and potential energy Now at the point ag re2=u²+2gh. ze2 sgt fos izo7 r = 12 + 2x10x.25 v=56 = 2045 m/s : Total energy at ng & = Tth = £me + nigh = 409691 v 6+29191 YIO X:25 - 209773 +241775 Te = 5AIN = 5.45N sred case : Just before hitting the ground the velocity will be o v2=u²eagh = 12+2x 10 x 15 = 11 m/s. Total energy & = TtV = T Tas v=o] = tmv² = fx.96918 11 1 I = 7465 N = 5145N i Kinetic energy conserved.

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