In: Advanced Math
Using the pigeonhole theorem prove that any set of 220 10-character strings over the alphabet {a,b,c,d} contains a pair of anagrams.
So the maximal set with no anagram pairs contain 286 strings. Which means there are some sets containing 220 strings such that the set doesn't contain any pair of anagrams.
I have used the formulas in the last calculation.
I don't think I have done any mistake. If you find any please comment. Otherwise the question is wrong, pigeonhole theorem can't be used here , to use that we need a set containing 287 or more strings.