Question

In: Statistics and Probability

Age Final Average Gender # Hrs Worked/wk Race Attendance 21 80 F 25 1 1 18...

Age Final Average Gender # Hrs Worked/wk Race Attendance
21 80 F 25 1 1
18 50 M 35 1 6
18 72 M 40 2 2
19 95 F 25 2 0
43 90 M 40 1 0
24 66 M 0 1 4
25 89 M 20 3 1
50 84 F 50 1 0
18 76 F 32 2 1
17 81 F 15 3 0
20 44 F 0 2 7
21 70 F 30 1 3
26 79 F 40 1 0
20 82 F 20 2 1

A study was conducted to determine the success rates of students enrolled in the Statistics courses offered at South Plains College for the fall semester of 2015. A random sample of 14 students was taken, and we recorded each student’s age, final average, gender, # hours worked per week, race, and the attendance record (# of classes not attended this semester). Use the results from the table to answer all parts of #2.

j. If one student is randomly selected from the sample, what is the probability that he/she will be over 25 years old? (2 pts)

k. For part j., did you use the classical, relative frequency (empirical), or subjective approach? (1 pt)

l. If three students are randomly selected, find the probability that at least one is a male. (3 pts)

m. Find the 90% confidence interval for the mean age of all Statistics students this semester. (3 pts)

REGRESSION ANALYSIS: FINAL AVERAGE (Y) VS. ATTENDANCE RECORD (X)

p. Construct a scatterplot (2 pts)

q. Compute the correlation coefficient (3 pts)

r. Compute the regression equation. (3 pts)

s. Predict the student’s final average if he/she has a total of 3 absences. (2 pts)

Solutions

Expert Solution

j)

Total number of students in a sample whoes age is over 25 years = 3

Total no of students in a sample = n = 14

Probability that the age of randomly selected student is over 25 is

We have used classical (relative frequency) approach.

Number of male students in a sample = 5

P( student being male ) = .   

Let X be the number of male students in a sample of 3 students. X follows binomobi distribution with probability of success p=0.3571

Probability that at least one male student = P(X>=1)

= 1-P(X=0) = .

90% confidence interval for the mean age of students

=

= (19.09,29.46)

Correlation between Age and final Average 0.3515

Regression Equation

Final average of a student with 3 absence

= 45.189+5.908(3)

=62.913

Scatter plot


Related Solutions

In 1955, Life Magazine reported that a 25-year-old mother of three worked, on average, an 80...
In 1955, Life Magazine reported that a 25-year-old mother of three worked, on average, an 80 hour week. Recently, many groups have been studying whether or not the women's movement has, in fact, resulted in an increase in the average work week for women (combining employment and at-home work). Suppose a study was done to determine if the mean work week has increased. 80women were surveyed with the following results. The sample mean was 83; the sample standard deviation was...
Female Student # Gender Height Shoe Age Hand 1 F 68 8.5 20 R 2 F...
Female Student # Gender Height Shoe Age Hand 1 F 68 8.5 20 R 2 F 60 5.5 27 R 3 F 64 7 31 R 4 F 67 7.5 19 R 5 F 65 8 20 R 6 F 66 9 29 R 7 F 62 9.5 30 L 8 F 63 8.5 18 R 9 F 60 5 19 L 10 F 63 7.5 42 R 11 F 61 7 20 R 12 F 64 7.5 17 R...
Student # Gender Height Shoe Age Hand 1 F 68 8.5 20 R 2 F 60...
Student # Gender Height Shoe Age Hand 1 F 68 8.5 20 R 2 F 60 5.5 27 R 3 F 64 7 31 R 4 F 67 7.5 19 R 5 F 65 8 20 R 6 F 66 9 29 R 7 F 62 9.5 30 L 8 F 63 8.5 18 R 9 F 60 5 19 L 10 F 63 7.5 42 R 11 F 61 7 20 R 12 F 64 7.5 17 R 13...
1. You want to create an 80% confidence interval for the average age of people who...
1. You want to create an 80% confidence interval for the average age of people who attend football games. You take a sample of 100 attendees and find the average age to be 43.7 years old with a standard deviation of 7 years. Find the value of t* for this confidence interval. 2. You want to make a 90% confidence interval for the difference in the percent of stray cats that are fixed and the percent of cats with homes...
1.) badBanana co. has an average age of inventory equal to 25 days. if its end...
1.) badBanana co. has an average age of inventory equal to 25 days. if its end of year inventory level is $8,500, then what does that imply for the cost of goods sold during the year? (round to the nearest dollar) a.) $582 b.) $4964 c.) $21,250 d.) $124,100 2.) What Ratio measures the ability of the firm to satisfy its short term obligations as they come due? a.) TImes Interest and earned ratio b.) current ratio c.) Inventory turnover...
Individual Age Gender (Male=1) Family Size Cigarettes/Day Alcohol/Day Total Claims 1 25 1 2 0 3...
Individual Age Gender (Male=1) Family Size Cigarettes/Day Alcohol/Day Total Claims 1 25 1 2 0 3 1 2 28 0 7 0 1 0 3 20 0 3 10 0 9 4 53 1 1 0 0 5 5 48 0 3 5 2 12 6 54 1 3 0 0 2 7 56 1 4 0 0 0 8 35 1 3 10 1 10 9 50 0 6 0 0 6 10 39 1 6 0 0 1...
Individual Television Radio 1 22 25 2 8 10 3 22 21 4 22 18 5...
Individual Television Radio 1 22 25 2 8 10 3 22 21 4 22 18 5 25 29 6 13 10 7 29 10 8 26 25 9 33 21 10 16 15 11 10 33 12 30 12 13 40 33 14 16 38 15 41 30 In recent years, a growing array of entertainment options competes for consumer time. By 2004, cable television and radio surpassed broadcast television, recorded music, and the daily newspaper to become the two...
1. Murphy’s Law, a pub in downtown Rochester, claims its patrons average 25 years of age....
1. Murphy’s Law, a pub in downtown Rochester, claims its patrons average 25 years of age. A random sample of 40 bar patrons is taken and their mean age is found to be 26.6 years with a standard deviation of 4.5 years. Do we have enough evidence to conclude at the level of significance α = 0.025 that, on average, patrons at Murphy’s Law are older than 25? Determine the test statistic. Determine the range of P-values. Write your decision...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT