In: Chemistry
1A: In 1999, scientists in israel developed a battery based on the followin cell reaction with iron(VI), nicknamed "super iron:" 2K2FeO4(aq)+3Zn(s)=Fe2O3(s)+ZnO(s)+2K2ZnO2(aq). In this reaction, identify the:
-species oxidized
-oxidizing agent
-in order to be a bettery, what must be true of Eo in the forward reaction?
1B: An electrolytic cell is based on the Cu2+/Cu and Ag+/Ag Half cells.
-Write the half reactions and the overall reaction
-Calculate Eo for this cell.
1A
The reaction is
2K2FeO4(aq)+3Zn(s)=Fe2O3(s)+ZnO(s)+2K2ZnO2(aq)
Clearly the oxidation of Fe in K2FeO4 is +6 and in Fe2O3 its +3 so, its getting reduced as oxidation state got decreases so, its the oxidising agent.
The Zn on the other hand has gained +2 oxidation state in ZnO compared to Zn so, Zn got oxidised.
In order to be a battery the forward reaction must be spontaneous which is the case when standard potential of the reaction is positive or E0 > 0
2A
The half cell chemical reactions are -
Ag+ + e -> Ag ---- E1 = 0.8 V (Chemistry Libre text)
Cu+2 + 2e -> Cu ----- E2 = 0.34 V (Chemistry Libre text)
To create a electrolytic cell the net voltage of the cell must be negative .
So, we need to reverse the reaction #1 and then add it to the second one but before that we must make sure that the electrons cancel out when we add them.
So, we multiply reaction #1 by 2 to get
2Ag+ + 2e -> 2Ag ---- G1 = -2FE1 = -2*F*0.8 V = -1.6F V
Cu+2 + 2e -> Cu ----- G2 = -2FE2 = -2*F(0.34 V) = -0.68F V
G is the change in Gibbs free energy G = -nFE where n is the no. of electrons involved in the hald reaction. F is the Faradays constant, E is the standard electrode potential.
Reversing reaction 1 we get
2Ag -> 2Ag+ + 2e ----- G1' = -2F(-E1) = -2*F(-(0.8 V)) = 1.6F V
Now adding this with reaction 2 we get
Cu+2 + 2e + 2Ag -> Cu + 2Ag+ + 2e
G = -2FEnet = G1' + G2 = -0.68F V + (1.6F V)
Cancelling out common electrons
Cu+2 + 2Ag -> Cu + 2Ag+
G = -2FEnet = -0.92F V
So, Enet = 0.92F / (-2F) V
Enet = - 0.46 V
So, standard potential for the overall reaction is Enet = -0.46 V
Negative value represents that the reaction needs external voltage to occur and thus its an electrolytic cell