Question

The power supply, the resistors and the wires can be connected such that the current drawn from the supply is smaller than the ratio of voltage provided by the power supply and the sum of all the resistors used.
	The power supply, the resistors and the wires can be connected such that the current drawn from the supply is larger than the ratio of voltage provided by the power supply and the sum of all the resistors used.
	The power supply, the resistors and the wires can be connected such that the current drawn is infinite, e.g., by shorting all resistors.
	The power supply, the resistors and the wires can be connected such that the voltage measured across one of the resistors can be greater than that supplied by the power supply. Explain which of these are true.

Answer 1

1st case is not possible, because whether we connect the resistors in series or in parallel or some series, some parallel , the current consumed is either greater than or equal to the ratio of the voltage supllied to the sum of all resistors.

2nd case is true, If we connect all the resistors in parallel then the current drawn from the supply is larger than the ratio of voltage provided by the power supply and the sum of all resistors. As for example we take two resistors R1 and R2 both in parallel to V. then since (R1+R2)^2>R1R2 so i=V/(R1||R2) is always less than V/(R1+R2).

3rd case is true..If the source resistance is assumed to be zer(theoritically) then the current drawn will be infinite by shorting all resistors no matter in what configuration they are connected.

4th case is not true. Since voltage will be dropped across a resistor. Applying KVL around any loop containg both the source and the resistor across which the voltage is desired to be measured ..,V= \(\sum_{i}^{}V_{i}\) where \(V_{i}\) are the absolute values of respective voltage drops actross each resistor , each being +ve.Thus can be less than or equal to V but can never be greater than V.