Question
In: Advanced Math
Draw bifurication diagram of: (x^2-a)(x^2-4)
Draw bifurication diagram of:
(x^2-a)(x^2-4)
Solutions
Expert Solution
Solution: For easy calculation i am assuming as x=y and a=u
so equation becomes y'=(y^2-u)(y^-4)
Colby Messinger answered 2 years agoRelated Solutions
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3. a) Draw a schematic diagram of an
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b) The results of an X-ray diffraction experiment that used
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i) Use this information to determine
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ii) An additional scan was performed
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Draw the interaction diagram (P-M diagram) of the column (16”x16” with 4#8 bars plus #3 tie...
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Given the following sample observations, draw a scatter diagram on a separate piece of paper. X:...
Given the following sample observations, draw a scatter
diagram on a separate piece of paper.
X:
−9
−14
13
1
16
Y:
51
243
159
4
338
Compute the correlation coefficient. (Round your answer
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Try squaring the x variable and then determine
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Given the following sample observations, draw a scatter diagram on a separate piece of paper. X:...
Given the following sample observations, draw a scatter diagram
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X:
−7
−16
13
3
16
Y:
54
241
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1
342
Click here for the Excel Data File
Compute the correlation coefficient. (Round your answer
to 3 decimal places.)
Does the relationship between the variables appear to be
linear?
Yes
No
Try squaring the x variable and then determine the
correlation coefficient. (Round your answer to 3 decimal
places.)
a)By hand, draw a scatter diagram treating x as the explanatory variable and y as the response variable
x
4
5
6
8
9
y
6
8
11
14
16
a)By hand, draw a scatter diagram treating x as the explanatory
variable and y as the response variable
b)Find the equation of the line containing the points (44,66)
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−16
11
1
16
Y:
50
248
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3
343
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Coefficient of correlation ________
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Yes
No
Try squaring the x variable and then determine the
correlation coefficient. (Round your answer to 3 decimal
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Coefficient of correlation ______
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------------------------------------------------------------------------------------------------------------------
USE Notation between transition:...
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