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Ignore the other questions in answering this one. If the magnetic field is 0.00546 T, the...

Ignore the other questions in answering this one. If the magnetic field is 0.00546 T, the accelerating voltage 150.7 V, and the radius of the electron orbit 0.750 cm, what is e/m from Equation 5?

Expert Solution

The kinetic energy (KE) of an accelerated electron will be equal to the energy gained by as a result of being accelerated through a potential difference (V).

where,

m is the mass of the electron

v is the velocity of the electron

e is the charge of an electron

V is the accelerating potential

If this electrons enters into a region where the magnetic field vector is acting perpendicular to the magnetic field (B), the magnetic force (F). The magnetic force in this condition is given by

This force experienced will be utilized for centripetal acceleration and hence the electron will inscribe a circular path of radius (r).

From the above equation,

Equating (1) and (2), we get,

Taking square on both sides,

Given,

V = 150.7 V

B = 0.00546 T

r = 0.750 cm = 0.750 x10-2m

= 1.7973 x 1011 C/kg (Ans.)

genius_generous answered 2 years ago

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