Question

In: Statistics and Probability

A researcher selected a random sample of 200 residents of Louisville, KY. The sample included 80...

  1. A researcher selected a random sample of 200 residents of Louisville, KY. The sample included 80 males and 120 females. The researcher asked the respondents to complete a survey that would measure the public trust in the police. This variable was coded 1 [low trust], 2 [average trust], and 3 [high trust]. Knowing that in each gender group 50% of the respondents acknowledged an average level of trust in the police and that 20 men and 20 women in the sample had a low level of trust in the police, (while the rest had a high level of trust in the police), determine if attitudes toward the police differ significantly by gender. In order to answer this question, you should also:                                                                                                                                [15 points]

                                                                                         

  1. Identify correctly the independent and the dependent variable [remember that the IV / the comparison groups should be the columns of the table]
  2. Create two contingency tables [Table 1 should include the observed and expected frequencies; Table 2 should include the percentages corresponding to various attitudes toward the police in each gender group (this would allow you to interpret the results)]
  3. Formulate the null and the alternative hypotheses
  4. Calculate the Chi-Square and test the null hypothesis after you calculate

Chi-Square -> C2 = S[(fo – fe)2/fe]

  1. Identify and record the critical Chi-square [see the table in your book] at the appropriate number of degrees of freedom and p<.05
  2. Reach a statistical conclusion and substantively interpret your findings [Hint: inspect the percentages in Table 2 (the total for each column should be 100%)]

Solutions

Expert Solution

Observed frequency  table
Low Average High Total
Male 20 40 20 80
Female 20 60 40 120
Total 40 100 60 200
E1= RT*CT/GT= 80*44/200 =16
Expected frequency  table
Low Average High Total
Male 16 40 24 80
Female 24 60 36 120
Total 40 100 60 200
H0: Attitudes toward the police differ insignificantly by gender.
H1: Attitudes toward the police differ significantly by gender.
CALCULATION TABLE
fo fe fo-fe (fo-fe)2/fe
Male L 20 16 4 1
Female L 20 24 -4 0.66666667
Male A 40 40 0 0
Female A 60 60 0 0
Male H 20 24 -4 0.66666667
Female H 40 36 4 0.44444444
SUM = 200 200 0 2.77777778
df=(3-1)(2-1)=2 fo=OBSERVED
level=0.05OR 5% fe= EXPECTED

Test statiatics Chi square =2.778

Crtical value of at 5% for 2df  = 5.99

and The P-Value =  0.24935

Statistical conclusion : Test statiatics Chi square =2.778 < 5.99

   or he P-Value (  0.24935) > 0.05

Fail to reject Ho

So we conclude that Attitudes toward the police differ insignificantly by gender.


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