You push a box of mass 17.4 kg with your car up to an icy hill...

You push a box of mass 17.4 kg with your car up to an icy hill slope of irregular shape to a height 5.1 m. The box has a speed 11.8 m/s when it starts up the hill, the same time that you brake. It then rises up to the top (with no friction) to a flat area before elastically colliding with a smaller box of mass 12 kg. The boxes then fall off a sheer cliff individually to the ground (with no drag).

(a) How far from the cliff does the heavier box hit the ground?

(b) What is the direction of motion of the heavier box as it hits the ground?
V= y + z

(c) How far from the cliff does the lighter box hit the ground?

(d) What is the direction of motion of the lighter box as it hits the ground? W= y + ẑ

Expert Solution

genius_generous answered 2 years ago

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