Question

In: Statistics and Probability

The president of a company that manufactures car seats has been concerned about the number and...

The president of a company that manufactures car seats has been concerned about the number and cost of machine breakdowns. The problem is that the machines are old and becoming quite unreliable. However, the cost of replacing them is quite high, and the president is not certain that the cost can be made up in today’s slow economy. To help make a decision about replacement, he gathered data about last month’s costs for repairs in dollars (y) and the ages in months (x) of the plant’s 20 welding machines as recorded :

Ages X Cost Y
110 655.34
113 753.36
114 785.04
134 886.28
93 685.24
141 952.32
115 649.48
115 677.96
115 866.9
142 1052.74
96 724.84
139 897.52
89 670.54
93 701.88
91 583.62
109 935.6
138 948.96
83 708.3
100 840.22
137 832.08

a) Find the estimated regression equation to predict the repair cost of a machine from its age.

b) Interpret the slope in the estimated regression equation.

c) Find and interpret the correlation between the repair cost of a machine and its age.

d) Find the coefficient of determination, and discuss what this statistic tells you.

Solutions

Expert Solution

Variables Ages X cost Y (x-x̅)(y-y̅) (x-x̅)2 (y- )
110 655.34 452.48785 11.2225 18244.17504
113 753.36 12.96785 0.1225 1372.776601
114 785.04 -3.49115 0.4225 28.847641
134 886.28 1979.69485 426.4225 9190.865161
93 685.24 2140.22985 414.1225 11060.93924
141 952.32 4476.78385 764.5225 26214.52428
115 649.48 -232.53615 2.7225 19861.54676
115 677.96 -185.54415 2.7225 12645.2274
115 866.9 126.20685 2.7225 5850.567121
142 1052.74 7515.72585 820.8225 68816.50424
96 724.84 1137.65685 301.0225 4299.556041
139 897.52 2747.34585 657.9225 11472.33788
89 670.54 2918.85885 592.9225 14369.05664
93 701.88 1801.60585 414.1225 7837.737961
91 583.62 4621.77885 499.5225 42762.51768
109 935.6 -631.57215 18.9225 21079.84572
138 948.96 3908.23285 607.6225 25137.7854
83 708.3 2492.06885 921.1225 6742.216321
100 840.22 -664.95015 178.2225 2480.936481
137 832.08 985.47185 559.3225 1736.305561
Total 2267 15808.22 35599.023 7196.55 311204.2692
Mean 113.35 790.411 1779.95115 359.8275 15560.21346

a) Regression equation is estimated by using the following equation

y = a + bx

where a and b are estimated by

  

Now according to the sum

Var(X) = 359.8275 VAR(Y) = 15560.21346

[ The detailed calculations are shown in the table ]

There fore a = 790.41 - (1779.95115 * 113.35 ) / 359.8275 = 229.7049

b = 1779.95115 / 359.8275 = 4.946679

Thus regression equation becomes

y = 229.7 + 4.95x

b) The slope is 4.95 which means for one month increase/decrease in age we will have an increment/decrement of 4.5 in the value of cost.

c ) correlation coefficient is found by the following formula

from the calculations done above we get the value of r to be

  

From this value it can be said that x and y are strongly correlated positively or in other words we can say there is a high positive corelation between the cost and the age of machine i.e. if the age of the machine increases then the cost of the machine increases and if the age decreases then the cost decreases.

d) Coefficient of determination is equal to r2 = (0.752234)2 = 0.5659

This means that 56.59% of the total variability of Y can be accounted for by its linear regression on X.R2 is a statistical measure of how close the data are to the fitted regression line. Therefore we can say that the data is 56.59% close to the fitted regression line.(y = 229.7 + 4.95x)


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