Red laser light with a wavelength of 633 nm shines on a surface with destructive interference...

Red laser light with a wavelength of 633 nm shines on a surface with destructive interference for that wavelength. The surface will appear:

1. white.

2. violet.

3. red.

4. black.

Expert Solution

The wavelength of light is 316.5 nm.

From the spectrum given below we see that this wavelength does not correspond to visible region (400 nm.- 700 nm).

So,it will not contain any colour out of 7 colour spectra we see in visible region.

The wavelength correspond to UV region.ans it will look black in colour because everything other than the visible region is dard in colour.

So,the correct option is BLACK.

As the wavelength 316.5 nm corresponds to UV region.

genius_generous answered 2 years ago

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