Question

a cube of osmium metal 1.500 cm on one of its sides. It also has the mass of 76.31g at 25°C please help me solve this problem by showing your work so I can compare my answers.
a. what is the density g/cm³ at this temp
b. the density of titanium metal 4.51g/cm³ at 25°C. what mass of titanium 'displaces' 68.8mL of water at 25°C
c. the density of benzene at 15°C is 0.8787 g/mL. determine the mass of 0.1900L of benzene at this temp.
Thank you so much!

Answer 1

a)

Given

Mass of Osmium metal = 76.31 g

Side of Os metal cube = 1.500 cm

Density of Os at 25 ⁰ C = ?

Density is calculated by using formula , density = Mass / volume

To calculate density we need to calculate volume of Os metal.

We know that, volume of cube = side ³

Volume of Os metal = ( 1.500 cm ) ³ = 3.375 cm ³

Substituting mass = 76.31 g and volume = 3.375 cm ³ in density formula, we get

Density = 76.31 g / 3.375 cm ³ = 22.61 g / cm ³

ANSWER : Density of Os at 25 ⁰ C : 22.61 g / cm ³

b)

Given

Density of Titanium metal =4.51 g / cm ³

Mass of Titanium that displaces 68.8 ml water = ?

When Ti metal is added to water, it will displace volume of water equal to its own volume.

Therefore, volume Ti = volume of water displaced = 68.8 ml.

We have formula, density = mass / volume

Mass of Ti = density volume

Mass of Ti = 4.51 g / cm ³ 68.8 cm ³ = 310.3 g

ANSWER : 310 g Titanium will displace 68.8 ml water.

c)

Given

Density of benzene = 0.8787 g /ml

Volume of benzene = 0.1900 L = 190 ml

Mass of 0.1900 L benzene = ?

We have formula, density = mass / volume

Mass of Benzene = density volume

Mass of Benzene = 0.8787 g / ml 190.0 ml = 166.95 g

ANSWER : Mass of 0.1900 L benzene is 167.0 g