In: Physics
Please check the underlined part in the solution
We know that time constant in RC circuit is given by:
= R*C
R = /C
Now given that C = 0.500 micro-farad = 0.500*10^-6 F
Part A.
minimum value of R will be when time constant is minimum, So
_min = 2.00 sec
Which will give:
R_min = _min/C
R_min = 2.00/(0.500*10^-6)
R_min = 4.0*10^6 ohm
R_min = 4.0 M-ohm
(I think you need final answer Mega ohms unit and not in miliohms If you need them in miliohm, then R = 4.0*10^6*10^3*10^-3 ohm = 4.0*10^9 miliohms)
Part B.
maximum value of R will be when time constant is maximum, So
_max = 15.00 sec
Which will give:
R_max = _max/C
R_max = 15.00/(0.500*10^-6)
R_max = 30.0*10^6 ohm
R_max = 30.0 M-ohm
(I think you need final answer Mega ohms unit and not in miliohms If you need them in miliohm, then R = 30.0*10^6*10^3*10^-3 ohm = 30.0*10^9 miliohms)
Let me know if you've any query.