Question

In: Math

Count iPhone User Id Price Willing to Pay 1 101 1150 2 204 800 3 205...

Count iPhone User Id Price Willing to Pay
1 101 1150
2 204 800
3 205 1050
4 405 1400
5 701 1050
6 105 1350
7 98 700
8 12 1450
9 37 800
10 55 650
11 68 750
12 31 1200
13 90 500
14 92 950
15 447 1050
16 778 1150

You are hired by Google to research how much people are willing to pay for a new cell phone in US. They are especially interested to know if their new phone, Pixel 3, should be priced similarly to Apple’s iPhone Xs. Google believes that there is a difference between what Android and iPhone users are willing to pay for high-end phones. You are hired to answer this question. Part I: To analyze iPhone users your team randomly selects 16 individuals. See attached data file.

a) Compute sample mean and sample standard deviation for iPhone users

b) Compute 5-number summary for iPhone users

c) Find the 90% confidence interval for the average phone price iPhone users are willing to pay. How do you interpret it?

Solutions

Expert Solution

sample mean=sum/n==3429/16=214.3125

sample standard deviation=sqrt(sum((x-)2)/(n-1))=sqrt(866799.4375/(16-1))=240.39

Count iPhone User Id(x) (x-214.3125)2 x-214.3125
1 101 -113.31 12839.72
2 204 -10.31 106.35
3 205 -9.31 86.72
4 405 190.69 36361.72
5 701 486.69 236864.72
6 105 -109.31 11949.22
7 98 -116.31 13528.60
8 12 -202.31 40930.35
9 37 -177.31 31439.72
10 55 -159.31 25380.47
11 68 -146.31 21407.35
12 31 -183.31 33603.47
13 90 -124.31 15453.60
14 92 -122.31 14960.35
15 447 232.69 54143.47
16 778 563.69 317743.60
sum= 3429 0 866799.4375
n= 16
sample mean=sum/n= 214.3125
sample sd= 240.3884963

(b) five number summery using R is given as

x=c(101,204,205,405,701,105,98,12,37,55,68,31,90,92,447,778)
> summary(x)
Min. 1st Qu. Median 3rd Qu. Max.
12.00 64.75 99.50 255.00 778.00

(c) (1-alpha)*100% confidence interval for population mean=sample mean±t(alpha/2,n-1)*s/sqrt(n)

90% confidence interval =214.3125±t(0.1/2, n-1)*240.39/sqrt(16)=214.3125±1.75*240.39/sqrt(16)=

214.3125±105.35=(108.96,319.67)

n= 16
sample mean= 214.3125
s= 240.39
t-value margin of error lower limit upper limit
95% confidence interval 2.13 128.09 86.22 342.41
99% confidence interval 2.95 177.09 37.22 391.40
90% confidence interval 1.75 105.35 108.96 319.67

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