A well insulated nozzle with a 0.005 m2 inlet cross section at 15 MPa and 673...

A well insulated nozzle with a 0.005 m2 inlet cross section at 15 MPa and 673 K water vapor enters at a speed of 25 m / s. The pressure of the steam-liquid mixture, whose quality is 80% at the nozzle outlet, was measured as 4.688 MPa. Work done on the nozzle is neglected. So,

a) Speed at the nozzle outlet (m / s)

b) Mass flow (kg / s),

c) Calculate the exit cross section of the nozzle (m2)

Expert Solution

steps:-

First we make a rough diagram of nozzle and name section 1-1 at inlet and section 2-2 outlet. from Steam table we obtained property of inlet and outlet of nozzle.

Apply energy equation between inlet and outlet .we consider only flow energy and kinetic energy other energy is does not change so don't write energy equation from here we find velocity of outlet of nozzle at last we calculate area of exit of nozzle and mass flow rate of steam

concept:- this is steam density is change at inlet and outlet we can't apply volume conservation lae here like water.we apply mass conservation law.

samet mamat answered 7 months ago

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