Question

A Ferris wheel with a diameter of 35.0 m in , starts from rest and achieves its maximum operational tangential speed of 2.20 m/s in a time of 15.0 s. a.) what is the magnitude of the wheel

Answer 1

Diameter (d) of the Ferris wheel = 35.0 m
Radius (r) of the Ferris wheel = (35.0m)/2
                                                = 17.5 m
Initial velocity (u) of the wheel = 0
Final velocity (v) of the wheel = 2.20 m/s
Time (t) taken to reach its maximum speed = 15.0 s

b)

Then linear acceleration (a) of the wheel is
                      a = (v - u)/t
                         = (2.20m/s - 0)/(15.0s)
                         = 0.147 m/s^2

a)

Then angular acceleration (a) of the wheel is
                     a = a / r

                        = (0.147 m/s^2) / (17.5m)

                        = 0.0084 rad/s^2