A 1500 kg car starts from rest and drives around a flat 50-m-diameter circular track. The...

A 1500 kg car starts from rest and drives around a flat 50-m-diameter circular track. The forward force provided by the car’s drive wheels is a constant 1000 N.
A. What are the magnitude and direction of the car’s acceleration at t = 10 s? Give the direction as an angle from the r-axis.

B. If the car has rubber tires and the track is concrete (use book or other reference to find coefficients of friction), at what time does the car begin to slide out of the circle?

Solutions

Expert Solution

a) Let's start with the tangential acceleration...

Next is the speed of the car so we can get the radial acceleration.

we know that radial acceleration,
so we get
Total acceleration =

Direction

b) The centripetal force is given as the following:
, where () is the constant for rubber on concrete which actually equals 1.

To calculate the time the car begins to slide out of the circle:

genius_generous answered 1 year ago

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