In: Advanced Math
Three frogs are placed on three vertices of a square. Every minute, one frog leaps over another frog, in such a way that the "leapee" is at the midpoint of the line segment whose endpoints are the starting and ending positions of the "leaper". Will a frog ever occupy the vertex of the square which was originally unoccupied?
Let us develop some terminology to help us better understand the problem.
We will say that the co-ordinate pair 
 is a lattice
point if both 
 and 
 are integers.
For example: 
 is a lattice
point while 
 is not.
Let us suppose, we have a unit square with vertices 
,
. 
and 
.
Without loss of generality, let us assume that the three frogs
are at the vertices 
, 
and 
respectively.
If not, we can always rotate the square to do so.
Another terminology! ...
 being even and
 being
odd, observe that 
, 
,
 and 
are of the form 
, 
, 
 and 
 respectively.
Claim is that the vertex 
 is
never occupied.
In fact, we will prove something stronger that we never reach
any point with 
 parity..
So, where do we start?.. It is only fair that we start from the beginning and use what is given to us.
Starting we have, before any leap is made, the occupied vertices
are 
, 
and 
.
What happens after the first leap made by anyone of the frogs?
Say, the frog at 
 leaps towards
the frog at 
. That means
 is the
mid-point of starting position 
 and the
ending position of the leaper, say, 
.
Solving, we get 
.
What did you observe? That the ending position is a lattice point.
Also, 
 is 
. And so is the ending position 
.
So, it leads us to think that given any point of time, the
positions occupied are lattice points with one of the parities
among 
, 
 and 
.
We will prove the same using the method of infinite descent.
i.e., for any positive integer 
, the occupied vertices
after 
leaps are lattice points with one of the parities among 
, 
 and 
.
We have shown it for 
 above.
Suppose that the result is true for 
.
i.e, the occupied vertices after 
 leaps are lattice
points with one of the parities among 
, 
 and 
.
So, what happens when a new leap has been made?
Suppose there is a frog at a point 
 which wants
to leap towards another frog at a point 
.
By previous result, 
 and 
are lattice points with one of the parities among 
, 
 and 
.
Now, where does the frog land?
Say, it lands at the point 
 where
are only real numbers to begin with. We do not know if they are
integers.
i.e., 
 is the
mid-point of 
 and 
.
and 
.
and 
.
That means 
 are integers.
Also, observe that 
So, if 
,
 or 
, then 
 would also
have to be 
, 
 and 
 respectively..
That means even after 
 leaps, the
occupied vertices are lattice points with one of the parities among
, 
 and 
.
Since 
 is any positive
integer, we have that the occupied vertices are lattice points with
one of the parities among 
, 
 and 
.
That means the vertex 
 is never
occupied. This finishes the proof.