In: Statistics and Probability
TABLE 1
X |
0 |
1 |
2 |
3 |
4 |
P(X = x) |
0.2 |
0.3 |
K |
0.15 |
0.1 |
value of K = 1-0.2-0.3-0.15-0.1 = 0.25
i)
X | P(X) | X*P(X) | X² * P(X) |
0 | 0.2000 | 0 | 0.000 |
1 | 0.3000 | 0.3 | 0.300 |
2 | 0.2500 | 0.5 | 1.0000 |
3 | 0.1500 | 0.45 | 1.3500 |
4 | 0.1000 | 0.4000 | 1.6000 |
.
expected defective parts= mean = E[X] = Σx*P(X) = 1.65
ii)
E [ X² ] = ΣX² * P(X) = 4.2500
variance = E[ X² ] - (E[ X ])² = 1.5275
std dev = √(variance) = 1.2359
iii)
P(0<x<3) = 0.30+0.25 = 0.55
2)
X~Bin(2,0.6)
Binomial probability is given by |
P(X=x) = C(n,x)*px*(1-p)(n-x) |
i)
X | P(X) |
0 | 0.1600 |
1 | 0.4800 |
2 | 0.3600 |
ii)