(a) The reaction of Al2(SO4)3 solution with NaOH forms a precipitate according to the equation: Al2(SO4)3...

(a) The reaction of Al₂(SO₄)₃ solution with NaOH forms a precipitate according to the equation: Al₂(SO₄)₃ (aq) + 6NAOH (aq) >>> 3Na₂SO₄ + 2Al(OH)₃.

(i) Which species is the precipitate?

(b) The addition of more NaOH causes the precipitate in the initial reaction to redissolve: Al(OH)₃ + NaOH >>> NaAl(OH)₄ (aq)

(ii) Write the formula of the complex ion.

(iii) Write the net ionic equation for this reaction.

(c) Finally, addition of an acid HCl to the solution in (b) causes a precipitate to form once more.

(iv) What chemical species is the precipitate?

(v) Write the net ionic equation for this reaction.

Expert Solution

queen_honey_blossom answered 3 years ago

How many moles of Al2(SO4)3 are there in 10.26 g of Al2(SO4)3?

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