After dissolving 1.430g of a mixture of Na2SO4 and Al2(SO4)3 in
water, you add an excess of BaCl2 solution. You filter off the
preciptitate which forms, dry it, and find that it weighs 2.54g.
What is the percent by mass of Al2(SO4)3 in the original mixture?
The first person who answered this was wrong. The answer is
supposed to be 33% but can someone show me how?