In: Physics
Let L = length of string = 2 m
Let M = mass of the string = 87 kg
Let T = tension on the string = 120 N
Let n = no. of loops on the string = no. of anti-nodes on the string = 3
Let λ = wavelength of wave on the string = 2.(L/n)
Let v = speed of wave on the string = [T / (M/L)]1/2
Let f = frequency of wave on the string = v / λ = ?
Wavelength of wave on the string, λ, is given by:
λ = 2 x (L/n)
Put L = 2 m and n =3 in the above equation and we get:
λ = 2 x (2 m / 3) = 1.33 m
λ = 1.33 m---------------------------(Eqn 1)
Speed of wave, v, is given by:
v = [T / (M/L)]1/2
Put T = 120 N, M = 87 kg and L = 2 m in the above equation and we get:
v = [120 N / (87 kg / 2 m)]1/2 = 1.66 m/s
v = 1.66 m/s-----------------------(Eqn 2)
Frequency of wave, f, is given by:
f = v / λ
Put v = 1.66 m/s and λ = 1.33 m from equations (2) and (1) in the above equation and we get:
f = 1.66 m/s / 1.33 m = 1.248 Hz
f = 1.248 Hz
f = 1.25 Hz--------------------------(answer)
(answer is rounded to three significant figures)
Answer: Frequency of the wave on the string is given by, f = 1.25 Hz