In: Physics
If 250 g of water is heated by 6 K during the experiment and the water-mass equivalent of the coil is 2.5 g, how many calories of energy has the water (and coil) absorbed? The specific heat capacity (using the archaic units of calories) is: 1 cal/(g K).
Sol. : We are given that temperature is raised by 6K of 250g water. Specific heat capacity of water = 1cal/(g K)
So heat absorbed by water = Q = msT = (250+2.5)16 = 1515 cal. [ Total mass of system is calculated]
We are given water equivalent mass of coil = 2.5g
Water equivalent mass is defined as the mass of water that will absorb or lose as same quantity of heat as the substance for the same change in temperature. Our system is in equilibrium means water water and coil has same temperature change.
So heat absorbed (or loss) by coil is same as heat absorbed by 2.5 g of water.
Heat absorbed by coil Qcoil = 2.516 = 15 cal.
So total heat absorbed by system = 1530 cal.
This is the required answer
Comment For further clarification.
Plz upvote if helps..