Question

In: Computer Science

Enter the first usable host address on the network 181.15.144.200 255.255.255.192. Please show work.

Enter the first usable host address on the network 181.15.144.200 255.255.255.192.

Please show work.

Solutions

Expert Solution

181.15.144.193

Explanation:
-------------
IP Address: 181.15.144.200
----------------------------------------
Let's first convert this into binary format
181.15.144.200
Let's convert all octets to binary separately
Converting 181 to binary
Divide 181 successively by 2 until the quotient is 0
   > 181/2 = 90, remainder is 1
   > 90/2 = 45, remainder is 0
   > 45/2 = 22, remainder is 1
   > 22/2 = 11, remainder is 0
   > 11/2 = 5, remainder is 1
   > 5/2 = 2, remainder is 1
   > 2/2 = 1, remainder is 0
   > 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 10110101
So, 181 of decimal is 10110101 in binary
181 in binary is 10110101

Converting 15 to binary
Divide 15 successively by 2 until the quotient is 0
   > 15/2 = 7, remainder is 1
   > 7/2 = 3, remainder is 1
   > 3/2 = 1, remainder is 1
   > 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 1111
So, 15 of decimal is 1111 in binary
15 in binary is 00001111

Converting 144 to binary
Divide 144 successively by 2 until the quotient is 0
   > 144/2 = 72, remainder is 0
   > 72/2 = 36, remainder is 0
   > 36/2 = 18, remainder is 0
   > 18/2 = 9, remainder is 0
   > 9/2 = 4, remainder is 1
   > 4/2 = 2, remainder is 0
   > 2/2 = 1, remainder is 0
   > 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 10010000
So, 144 of decimal is 10010000 in binary
144 in binary is 10010000

Converting 200 to binary
Divide 200 successively by 2 until the quotient is 0
   > 200/2 = 100, remainder is 0
   > 100/2 = 50, remainder is 0
   > 50/2 = 25, remainder is 0
   > 25/2 = 12, remainder is 1
   > 12/2 = 6, remainder is 0
   > 6/2 = 3, remainder is 0
   > 3/2 = 1, remainder is 1
   > 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 11001000
So, 200 of decimal is 11001000 in binary
200 in binary is 11001000

=====================================================================================
||    181.15.144.200 in binary notation is 10110101.00001111.10010000.11001000    ||
=====================================================================================

Subnet address: 255.255.255.192
----------------------------------------
Let's convert this into binary format
255.255.255.192
Let's convert all octets to binary separately
Converting 255 to binary
Divide 255 successively by 2 until the quotient is 0
   > 255/2 = 127, remainder is 1
   > 127/2 = 63, remainder is 1
   > 63/2 = 31, remainder is 1
   > 31/2 = 15, remainder is 1
   > 15/2 = 7, remainder is 1
   > 7/2 = 3, remainder is 1
   > 3/2 = 1, remainder is 1
   > 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 11111111
So, 255 of decimal is 11111111 in binary
255 in binary is 11111111

Converting 192 to binary
Divide 192 successively by 2 until the quotient is 0
   > 192/2 = 96, remainder is 0
   > 96/2 = 48, remainder is 0
   > 48/2 = 24, remainder is 0
   > 24/2 = 12, remainder is 0
   > 12/2 = 6, remainder is 0
   > 6/2 = 3, remainder is 0
   > 3/2 = 1, remainder is 1
   > 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 11000000
So, 192 of decimal is 11000000 in binary
192 in binary is 11000000

======================================================================================
||    255.255.255.192 in binary notation is 11111111.11111111.11111111.11000000    ||
======================================================================================

Remove all dots to form 11111111111111111111111111000000
Remove all 0's from the right side to form 11111111111111111111111111
Number of 1's in this is 26
so, Subnet mask is /26

For Calculating network ID, keep first 26 bits of 10110101.00001111.10010000.11001000 and set all remaining bits to 0.
so, network ID in binary is 10110101.00001111.10010000.11000000
10110101.00001111.10010000.11000000:
----------------------------------------
10110101.00001111.10010000.11000000
Let's convert all octets to decimal separately
Converting 10110101 to decimal
Converting 10110101 to decimal
10110101
=> 1x2^7+0x2^6+1x2^5+1x2^4+0x2^3+1x2^2+0x2^1+1x2^0
=> 1x128+0x64+1x32+1x16+0x8+1x4+0x2+1x1
=> 128+0+32+16+0+4+0+1
=> 181
10110101 in decimal is 181

Converting 00001111 to decimal
Converting 00001111 to decimal
00001111
=> 0x2^7+0x2^6+0x2^5+0x2^4+1x2^3+1x2^2+1x2^1+1x2^0
=> 0x128+0x64+0x32+0x16+1x8+1x4+1x2+1x1
=> 0+0+0+0+8+4+2+1
=> 15
00001111 in decimal is 15

Converting 10010000 to decimal
Converting 10010000 to decimal
10010000
=> 1x2^7+0x2^6+0x2^5+1x2^4+0x2^3+0x2^2+0x2^1+0x2^0
=> 1x128+0x64+0x32+1x16+0x8+0x4+0x2+0x1
=> 128+0+0+16+0+0+0+0
=> 144
10010000 in decimal is 144

Converting 11000000 to decimal
Converting 11000000 to decimal
11000000
=> 1x2^7+1x2^6+0x2^5+0x2^4+0x2^3+0x2^2+0x2^1+0x2^0
=> 1x128+1x64+0x32+0x16+0x8+0x4+0x2+0x1
=> 128+64+0+0+0+0+0+0
=> 192
11000000 in decimal is 192

======================================================================================
||    10110101.00001111.10010000.11000000 in decimal notation is 181.15.144.192    ||
======================================================================================
=============================================
||    So, Network ID is 181.15.144.192    ||
=============================================

For Calculating first valid address in subnet, add 1 to the network address.
Network Address is 181.15.144.192
================================================================
||    So, first valid address in subnet is 181.15.144.193    ||
================================================================

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