Question

In: Economics

Lyuba has preferences over peonies (p) and tulips (t). The following list shows all feasible bundles...

  1. Lyuba has preferences over peonies (p) and tulips (t). The following list shows all feasible bundles that Lyuba can consume in a month:

    A = (pA,tA) = (1,3), B = (pB,tB) = (3,1), C = (pB,tB) = (2,2).
    If Lyubas preferences are given by: A is indifferent to B, C is strictly preferred to A

    and C is strictly preferred to B, then:

    1. (a) A function that represents Lyuba’s preferences is U(p,t)=3p+t.

    2. (b) A function that represents Lyuba’s preferences is U(p,t)=p+t.

    3. (c) There exists a utility function different from the ones mentioned above that rep- resents Lyuba’s preferences.

    4. (d) None of the above.

Solutions

Expert Solution

Given Lyuba's preferences over peonies(p) and tulips(t) with feasible bundles over a month.

The preferences are listed as:

A= (pt, tA) = (1,3)

B= (pB, tB) = (3,1)

C = (pC, tC) = (2,2)

Given, Lyubas's preferences are ordered as:

She is indifferent between A and B, so utility from A is equal to utility from B, u(A) = u(B) ;

C is strictly preferred to A, so utility from C is greater than utility from A, u(C) > u(A) ;

and C is strictly preferred to B, so utility from C is greater than utility from B, u(C) > u(B).

(a) Utility represented as U(p,t) = 3p + t cannot be Lyuba's utility function because in this case, A= (pt, tA) = (1,3), putting values of p=1 and t =3 so u(A) = 3(1) + 3 = 6; B= (pB, tB) = (3,1); putting values of p = 3 and t = 1 so u(B) = 3(3) + 1 = 10.

This option is incorrect because in this case u(A) < u(B).

(b) Utility represented as U(p,t) = p + t cannot be Lyuba's utility function because in this case, A= (pt, tA) = (1,3), putting values of p=1 and t =3 so u(A) = 1 + 3 = 4; B= (pB, tB) = (3,1); putting values of p = 3 and t = 1 so u(B) = 3 + 1 = 4 ; C = (pC, tC) = (2,2), putting values of p = 2 and t = 2 so u(C) = 2 + 2 =4.

This option is incorrect because in this case u(A) = u(B) = u(C).

(c) This option is correct because there exists a utility function different from above that represents Lyuba's preferences.

For instances u(pA, tB) = pt represents her utility function.

In this case: utility from A = 1 * 3 = 3 , where p=1 and t=3;

utility from B = 3 * 1 = 3, where p=3 and t=1;

and utility from C = 2 * 2 = 4, where p =2 and t =2;

Here u(A) =u(B), u(C) > u(A) and u(C) > u(B).

(d) This is an incorrect option as option C is correct.


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