Question

In: Physics

Two 2.0 kg bodies, A and B, collide. The velocities before the collision are: vA =(15iˆ-30jˆ)m/s...

Two 2.0 kg bodies, A and B, collide. The velocities before the collision are: v_A =(15iˆ-30jˆ)m/s and :v_B =(-10iˆ-5.0jˆ)m/s. After the collision, :v_fA = (-5.0iˆ - 20jˆ ) m/s. What are (a) the final velocity of B and (b) the change in the total kinetic energy (including sign)?

Expert Solution

Given, Mass of body A ( ma ) = 2 kg

Mass of body B ( mb ) = 2 kg

Initial velocity of body A ( via ) =

Initial velocity of body B ( vib ) =

Final velocity of body A ( vfa ) =

(a) We have to calculate final velocity of body B ( vfb ).

As there is no external force is acting on the sytem of two bodies.

Therefore, the momentum must be conserved.

So, final momentum = initial momentum

Putting the values in above equation

Solving the above equation, we get

(b) We have to calculate the change in total kinetic energy.

Initial Kinetic Energy ( Ei ) =

=

Final Kinetic Energy ( Ef ) =

=

Change in Kinetic Energy ( ) =

=

genius_generous answered 7 months ago

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