A rock is thrown upward from a bridge that is 83 feet above a road. The rock reaches its maximum height above the road 0.61 seconds after it is thrown and contacts the road 3.87 seconds after it was thrown.

Write a function f that determines the rock's height above the road (in feet) in terms of the number of seconds tt since the rock was thrown. THE FUNCTION MUST BE IN THE FORMAT f(t)=c⋅(t−t_1)(t−t_2) for fixed numbers c, t_1, and t_2. NOT f(x)= -16t^2+40.47297t+83 I already know how to do that.

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The complete solution is provided in the attachments.

milcah answered 1 year ago

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