In: Math
group | hours |
1.00 | 44.00 |
1.00 | 40.00 |
1.00 | 44.00 |
1.00 | 39.00 |
1.00 | 25.00 |
1.00 | 37.00 |
1.00 | 31.00 |
1.00 | 40.00 |
1.00 | 22.00 |
1.00 | 34.00 |
1.00 | 39.00 |
1.00 | 20.00 |
1.00 | 39.00 |
1.00 | 42.00 |
1.00 | 41.00 |
2.00 | 36.00 |
2.00 | 40.00 |
2.00 | 37.00 |
2.00 | 35.00 |
2.00 | 39.00 |
2.00 | 40.00 |
2.00 | 36.00 |
2.00 | 38.00 |
2.00 | 24.00 |
2.00 | 27.00 |
2.00 | 29.00 |
2.00 | 24.00 |
2.00 | 45.00 |
2.00 | 44.00 |
2.00 | 44.00 |
3.00 | 52.00 |
3.00 | 50.00 |
3.00 | 51.00 |
3.00 | 52.00 |
3.00 | 45.00 |
3.00 | 49.00 |
3.00 | 47.00 |
3.00 | 46.00 |
3.00 | 47.00 |
3.00 | 47.00 |
3.00 | 46.00 |
3.00 | 45.00 |
3.00 | 50.00 |
3.00 | 47.00 |
3.00 | 49.00 |
The senior class at a charter school specializing in the physical sciences surveyed students in three specialization tracks; physics, chemistry and math.
Using the data provided above. Provide the answers to the following questions starting with:
The null hypothesis for this study is u physics = u chemistry = u math
1. The alternate hypothesis is:
a. u physics =/= u math =/= u chemistry
b. All of the means are different
c. At least 2 of the means are different
d. At least two of the means are the same
2. The Value of the ANOVA statistic (F) is:
3. The probability that we would get this large a value for ANOVA is (p value):
4. Based on this result we would draw which conclusion
a. Reject the null hypothesis and accept the alternative hypothesis that at least two of the population means are different
b. Reject the null hypothesis and accept the alternative hypothesis that at least two of the sample means are different
c. Reject the null hypothesis and accept the alternative hypothesis that all of the population means are different
d. Fail to Reject the null hypothesis
using SPSS>analyze>means>one way ANOVA
ANOVA
hours
Sum of Squares df Mean Square
F Sig.
Between Groups 1529.378 2
764.689 20.016 .000
Within Groups 1604.533 42
38.203
Total 3133.911 44
The null hypothesis for this study is u physics = u chemistry = u math
1. The alternate hypothesis is:
c. At least 2 of the means are different
2. The Value of the ANOVA statistic (F) is: 20.016
3. The probability that we would get this large a value for ANOVA is (p value): 0.000
4. Based on this result we would draw which conclusion
a. Reject the null hypothesis and accept the alternative hypothesis that at least two of the population means are different