Question

In: Math

group hours 1.00 44.00 1.00 40.00 1.00 44.00 1.00 39.00 1.00 25.00 1.00 37.00 1.00 31.00...

group hours
1.00 44.00
1.00 40.00
1.00 44.00
1.00 39.00
1.00 25.00
1.00 37.00
1.00 31.00
1.00 40.00
1.00 22.00
1.00 34.00
1.00 39.00
1.00 20.00
1.00 39.00
1.00 42.00
1.00 41.00
2.00 36.00
2.00 40.00
2.00 37.00
2.00 35.00
2.00 39.00
2.00 40.00
2.00 36.00
2.00 38.00
2.00 24.00
2.00 27.00
2.00 29.00
2.00 24.00
2.00 45.00
2.00 44.00
2.00 44.00
3.00 52.00
3.00 50.00
3.00 51.00
3.00 52.00
3.00 45.00
3.00 49.00
3.00 47.00
3.00 46.00
3.00 47.00
3.00 47.00
3.00 46.00
3.00 45.00
3.00 50.00
3.00 47.00
3.00 49.00

The senior class at a charter school specializing in the physical sciences surveyed students in three specialization tracks; physics, chemistry and math.

Using the data provided above. Provide the answers to the following questions starting with:

The null hypothesis for this study is u physics = u chemistry = u math

1. The alternate hypothesis is:

a. u physics =/= u math =/= u chemistry

b. All of the means are different

c. At least 2 of the means are different

d. At least two of the means are the same

2. The Value of the ANOVA statistic (F) is:

3. The probability that we would get this large a value for ANOVA is (p value):

4. Based on this result we would draw which conclusion

a. Reject the null hypothesis and accept the alternative hypothesis that at least two of the population means are different

b. Reject the null hypothesis and accept the alternative hypothesis that at least two of the sample means are different

c. Reject the null hypothesis and accept the alternative hypothesis that all of the population means are different

d. Fail to Reject the null hypothesis

Solutions

Expert Solution

using SPSS>analyze>means>one way ANOVA

ANOVA                  
hours
  Sum of Squares df   Mean Square   F   Sig.
Between Groups   1529.378   2   764.689   20.016   .000
Within Groups   1604.533   42   38.203      
Total 3133.911   44      

  

The null hypothesis for this study is u physics = u chemistry = u math

1. The alternate hypothesis is:

c. At least 2 of the means are different

2. The Value of the ANOVA statistic (F) is: 20.016

3. The probability that we would get this large a value for ANOVA is (p value): 0.000

4. Based on this result we would draw which conclusion

a. Reject the null hypothesis and accept the alternative hypothesis that at least two of the population means are different


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