In: Statistics and Probability
Unoccupied seats on flights cause airlines to lose revenue. Suppose a large airline wants to determine of the mean number of unoccupied seats on all its flights is greater than 10. To accomplish this, the records of 60 flights are randomly selected and the number of unoccupied seats is noted for each of the sampled flights. The sample mean is 11.4 seats and the sample standard deviation is 3.4 seats. Test the claim that mean number of unoccupied seats on all its flights is greater than 10 at the 5% significance level.
This is the two tailed test .
The null and alternative hypothesis is
H0 : = 10
Ha : > 10
Test statistic = t
= ( - ) / s / n
= (11.4 - 10) / 3.4 / 60
= 3.190
Test statistic = .190
df = 59
P-value = 0.0011
= 0.05
P-value <
Reject the null hypothesis .
There is sufficient evidence to conclude that the claim that mean number of unoccupied seats on all its flights is greater than 10 at the 5% significance level.