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4. (20) A stoichiometric mixture of CO and O2 enters a reactor at 100 oC. CO2,...

4. (20) A stoichiometric mixture of CO and O₂ enters a reactor at 100 ^oC. CO₂, CO and O₂ leave the reactor in chemical equilibrium at 1527 ^oC and 2 atm. Calculate the partial pressures of CO₂, CO and O₂ in the products.

CO + ½ O₂ = CO₂: ΔG^o_373K = -250.8 kJ

CO + ½ O₂ = CO₂: ΔG^o_1800K = -127.4 kJ

Expert Solution

Data provided

G0 ( 373 K ) = -250.8 KJ = -250800 J

G0 ( 1800 K ) = -127.4 KJ = - 127400 J

Reaction

CO + ½ O2 = CO2

Products leave the reactor at 1800 K

free energy can be given as

G0 = - RT ln ( K )

here

R = gas constant = 8.314 J /mol K

T = temperature K

K = equilibrium constant of a reaction for stoichiometry

Rearranging above equation

Amanda K answered 6 months ago

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