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a) Fick’s second law and its application
b) Different Mass transfer coefficients
c) Raoult’s law and Henry’s law and their applications
d) Give the jD correlation for mass transfer in flow parallel to flat plate
e) Chilton – Colburn analogy
f) Capacity coefficients and their use
g) Marangony effect
4) a) Explain briefly about the diffusivities in gases
b) Explain briefly about the diffusivities in liquids
b) Predict the diffusion coefficients of dilute electrolytes for the following cases:
i) For KCl at 25 0C, calculate .
ii) For KCl at 18.5 0C, calculate .
iii) For CaCl2 at 25 0C, calculate . Also predict Di of ion Ca+2 and of Cl-.
Data: λ+(K+) =73.5, λ-(Cl-) =76.3, λ+(Ca2+/2) = 59.5
6) Explain (a) The two film theory and (b) The penetration theory.
7) Explain the mass transfer in the laminar boundary layer when the fluid is in laminar flow over a flat plate.
8).Explain the following briefly.
As we know that ficks first law is applicable for steady state molecular diffusion but ficks second law is applicable for unsteady state molecular diffusion. It means here accumulation of concentration within volume is there.
By ficks second law,
dCa/dt = Dab*d2Ca/dt2
It is applicable for one dimensional unsteady state molecular diffusion.
Ca - concentration of diffusing component.
Dab is the diffusivity of A and B.
t is the time.
Application : this law is applicable for all unsteady state mass transfer operations. It tells us how much flux is gone through the system and what is the accurate time. Equation having time and space simultaneously so it tells both .
b) we have different - different mass transfer coefficients:
Flux = mass transfer coefficient * concentration difference
Mass transfer coefficient basis of Diffusing A and Non diffusing B (Nb = 0)
Na = kg*(ΔP) = ky(Δy) = kc(ΔC)
kg - mass transfer coefficient in terms of gas pressure.
ky - mass transfer coefficient in terms of mole fractions in gas phase.
kc - mass transfer coefficient in terms of concentration in gas phase.
Similarly for liquid phase,
Na = kx*(Δx) = kL(ΔC)
kx - mass transfer coefficient in terms of mole fraction in liquid phase.
kL - mass transfer coefficient in terms of concentration in liquid phase.
Equimolar countercurrent mass transfer (Na = - Nb)
All mass transfer coefficient is based on equimolar countercurrent mass transfer.
Na = kg'(ΔP) = ky'(Δy) = k'c(ΔC)
kg', ky' , kc' - mass transfer coefficients are based on pressure, mole fraction, and concentration in gas phase.
Na = k'x(Δx) = kL'(ΔC)
kx', kL' are mass transfer coefficients are based on mole fraction and concentration in liquid phase.
C) roults law and henry law and their application :
Roults law - it is applicable for all ideal solutions of liquid and vapor. Here solute is very much soluble into the solvent.
If gas and liquid are in equilibrium then
yP = xP*
y =(P*/P )* x = mx
Where y is the mole fraction of solute in gas phase.
x is the mole fraction of solute in liquid phase.
P is the total pressure.
P* is the vapor pressure of liquid in that temperature.
Application : this law is so much applicable in mass transfer operations in chemical industry for using equilibrium relation in distillation column and other mass transfer operations.
Where we found data between more volatile and less volatile component and by which we get separation themselves.
Henrys law: it is applicable for solute which having less solubility into the gases. It is used for finding solubility of liquid into the gases.
y = Hx
H is the henry law coefficient.
Application : this law is used to find out the solubility of the liquid and gas into the other solvents. Like O2 solubility into the water and so. Much examples which are found out by this law and also use in mass transfer operations and chemical Operation in industry.
D) Jd corellation for mass transfer in flow parallel to flat plate
As we know that
Mass transfer factor Jd =( Std) *(Sc) ^(2/3
Where (Std) is the Stanton number for diffusion.
Std = Sh/ReSc
For parallel flat plate,
Sh = 0.664*Re^0.5 * Sc^(1/3)
Std = (0.664*Re^0.5 * Sc^(1/3)/ReSc = 0.664Re^-0.5 * Sc(-2/3)
Then
Jd = 0.664*Re^-0.5