In: Statistics and Probability
7. A biologist was interested in determining whether sunflower seedlings treated with an extract from Vincaminor roots resulted in a lower mean height of sunflower seedlings than the standard height of 15.7 cm. The biologist treated a random sample of n = 33 seedlings with the extract and subsequently obtained the a sample mean of 15.664 cm and a sample standard deviation of 2.544 cm. Test the claim that the mean height is less than 15.7 cm. Fill in the following information as you test the above claim: State the claim symbolically and the opposite of the claim.
H0 :
H1 :
Teststatistic: |
P-value: |
Conclusion: |
olution :
Given that,
Population mean = = 15.7
Sample mean = = 15.664
Sample standard deviation = s = 2.544
Sample size = n = 33
Level of significance = = 0.05
This is a left tailed test.
The null and alternative hypothesis is,
Ho: 15.7
Ha: < 15.7
The test statistics,
t = ( - )/ (s/)
= ( 15.664 - 15.7 ) / ( 2.544 /33)
= -0.081
p-value = 0.4679
The p-value is p =0.4679 > 0.05 it is concluded that the null hypothesis is fails to rejected.
Conclusion :
It is concluded that the null hypothesis Ho is fails to rejected. Therefore, there is not enough evidence to claim that the
population mean μ is less than 15.7, at the 0.05 significance level.