In: Economics
Consider the two investments shown below, only one of which can be chosen. They are one-shot investments. Calculate AW2-1 assuming 10.8354 interest rate.
| 
 EOY  | 
 Alternative 1  | 
 Alternative 2  | 
| 
 0  | 
 - 20,369  | 
 - 56,679  | 
| 
 1  | 
 3,844  | 
 1,000  | 
| 
 2  | 
 3,844  | 
 1,800  | 
| 
 3  | 
 3,844  | 
 2,600  | 
| 
 4  | 
 3,844  | 
 3,400  | 
| 
 5  | 
 3,844  | 
 4,200  | 
| 
 6  | 
 5,000  | 
|
| 
 7  | 
 5,800  | 
|
| 
 8  | 
 6,600  | 
Solution
In the given question first we will find out the NPV of both the projects
Then Annual worth= NPV*[(i(1+i)^n)/(1+i)^n-1
Where NPV= net present value of project
I =rate of interest= 10.8354%
n= life of project
NPV= Sum of Present value of all cash flows- Initial investment
The calculations have been given in table below
| 
 Year  | 
 Alternative 1  | 
 Present value  | 
 Alternative 2  | 
 Present value  | 
| 
 0  | 
 -20369  | 
 -20369  | 
 -56679  | 
 -56679  | 
| 
 1  | 
 3844  | 
 3547.6309  | 
 1000  | 
 902.2388  | 
| 
 2  | 
 3844  | 
 3274.1116  | 
 1800  | 
 1465.2628  | 
| 
 3  | 
 3844  | 
 3021.6804  | 
 2600  | 
 1909.5801  | 
| 
 4  | 
 3844  | 
 2788.7115  | 
 3400  | 
 2253.0195  | 
| 
 5  | 
 3844  | 
 2573.7042  | 
 4200  | 
 2511.0585  | 
| 
 6  | 
 NPV  | 
 -5163.1613  | 
 5000  | 
 2697.1124  | 
| 
 7  | 
 5800  | 
 2822.7898  | 
||
| 
 8  | 
 6600  | 
 2898.1175  | 
||
| 
 NPV  | 
 -39219.8207  | 
Now annual worth Alternative 1= -5163.1613*[(.108354*(1.108354^5))/1.108354^5-1)
= -1391.2184
Now Annual worth Alternative 2= -39219.8207*[(.108354*(1.108354^8))/1.108354^8-1)
= -7576.5564
Therefore Alternative 1 is better, has higher annual worth