In: Economics
Consider the two investments shown below, only one of which can be chosen. They are one-shot investments. Calculate AW2-1 assuming 10.8354 interest rate.
EOY |
Alternative 1 |
Alternative 2 |
0 |
- 20,369 |
- 56,679 |
1 |
3,844 |
1,000 |
2 |
3,844 |
1,800 |
3 |
3,844 |
2,600 |
4 |
3,844 |
3,400 |
5 |
3,844 |
4,200 |
6 |
5,000 |
|
7 |
5,800 |
|
8 |
6,600 |
Solution
In the given question first we will find out the NPV of both the projects
Then Annual worth= NPV*[(i(1+i)^n)/(1+i)^n-1
Where NPV= net present value of project
I =rate of interest= 10.8354%
n= life of project
NPV= Sum of Present value of all cash flows- Initial investment
The calculations have been given in table below
Year |
Alternative 1 |
Present value |
Alternative 2 |
Present value |
0 |
-20369 |
-20369 |
-56679 |
-56679 |
1 |
3844 |
3547.6309 |
1000 |
902.2388 |
2 |
3844 |
3274.1116 |
1800 |
1465.2628 |
3 |
3844 |
3021.6804 |
2600 |
1909.5801 |
4 |
3844 |
2788.7115 |
3400 |
2253.0195 |
5 |
3844 |
2573.7042 |
4200 |
2511.0585 |
6 |
NPV |
-5163.1613 |
5000 |
2697.1124 |
7 |
5800 |
2822.7898 |
||
8 |
6600 |
2898.1175 |
||
NPV |
-39219.8207 |
Now annual worth Alternative 1= -5163.1613*[(.108354*(1.108354^5))/1.108354^5-1)
= -1391.2184
Now Annual worth Alternative 2= -39219.8207*[(.108354*(1.108354^8))/1.108354^8-1)
= -7576.5564
Therefore Alternative 1 is better, has higher annual worth