In: Math
Problem 6.
1. If X N(9; 4), nd Pr(jX ? 2j < 4).
2. If X N(0; 1), nd Pr(jX + 3j > 5).
3. If X N(?2; 9), nd the number c such that Pr(jX + 2j < c) =
0:5.
1] If X N(9; 4), find
=
=
= 0.06680720 - 0.000000000189
= 0.06680718
2. If X N(0; 1), find
= 1 - [ 0.977250 - 0.000000006 ]
= 0.02275
3. If X N(-2; 9), find the number c such that = 0.5
= 0.5
= 0.5
= 0.5
= 0.5
Where Z is Standard normal variate
= 0.5
= 0.5
= 0.75
c/3 = 0.67449
c = 2.023469