Question

In: Physics

During the 2004 Olympic Games, a shot putter threw a shot put with a speed of...

During the 2004 Olympic Games, a shot putter threw a shot put with a speed of 12.1 m/s at an angle of 43.7° above the horizontal. She released the shot put from a height of 2.07 m above the ground.

a) How far did the shot put travel in the horizontal direction?

b) How long was it until the shot put hit the ground?

Expert Solution

This is a Projectile Motion Which are Pretty Standard.

The First Step in Projectile Motion is to Divide Velocity in to x,y Components.

Now we have to Take our velocity componrnt which will solve the given question

a)in here we need to use x component ,observe that we dont have any Horizontal Forces acting on shot put.

Hence Horizontal Distance = V*t =

where t is the total time travelled.

b)in projectile motion we have a direct Derivation for Flight time which is

But we also have to cover 2.07 m

Using

Solving For t = 0.21940338695453243 sec

Total Time = 1.706 + 0.21940338695453243 = 1.92540338695 sec===>Answer B

a)

genius_generous answered 6 months ago

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