In: Physics
An empty tin can with height of 30cm and a diameter of 15cm is open at one end and closed at the other end. If the vertical can, with open end down, be slowly immersed in water, how far the water will rise inside the can when the closed end is 10 cm below the water surface?
SOLUTION:
The white portion in the figure is air and the blue region is water.
Let h be the height in meters of the air column.
From hydrostatic paradox, we have, Hydrostatic pressure at point A = Hydrostatic pressure at point B.
Pressure at point B is given by:
= depth of water to point B =
g = acceleration due to gravity = 9.8 m/s2
Similarly, Pressure at point A (due to air) is given by:
We have,
Cancelling out g:
Density of water = 1000 kg/m3
Density of air = 1.2 kg/m3
Therefore, Height at which the water rises,
Height at which the water rises is 20 cm.