In: Finance
6.
Investment A will make N annual payments of $500 with the first of the N payments due immediately. Investment A has a value of $20,000. Investment B is an ordinary annuity that will make (N minus 1) annual payments of $500 with the first payment due in one year from today. If investment A and investment B have the same expected return, then what is the value of investment B?
$20,500 |
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The value of investment B can not be determined from the information given |
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The value of investment B can be determined from the information given, but it is not equal to $19,500, $20,000, or $20,500 |
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$20,000 |
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$19,500 7. Investment A will make N annual payments of $500 with the first of the N payments due immediately. Investment B is an ordinary annuity that will make (N minus 1) annual payments of $500 with the first payment due in one year from today. Investment B has a value of $20,000. If investment A and investment B have the same expected return, then what is the value of investment A?
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6 | INVESTMENT A | |||||||||||
Annual payment at the beginning of the year | $500 | |||||||||||
Present Value of payment | $20,000 | |||||||||||
Assume number of payments(N) | 80 | |||||||||||
Interest rate | 2.05% | (Using RATE functionof excel with Nper=80, Pmt=500,PV=-20000, Type=1(Beginning of year payment) | ||||||||||
INVESTMENT B | ||||||||||||
Annual payment at the end of the year | $500 | |||||||||||
Number of payments(N-1) | 79 | |||||||||||
Interest rate | 2.05% | |||||||||||
Present Value of payment | $19,500 | (Using PV functionof excel with RATE=2.05%.Nper=79, Pmt=500,Type=0(End of year payment) | ||||||||||
ANSWER: | ||||||||||||
$19,500 | ||||||||||||
It will be $19,500for any value of N | ||||||||||||
Because in the investment B ,the first payment of $ 500immediately is not made. | ||||||||||||
7 | INVESTMENT B | |||||||||||
Annual payment at the end of the year | $500 | |||||||||||
Present Value of payment | $20,000 | |||||||||||
Assume number of payments(N) | 79 | |||||||||||
Interest rate | 1.96% | (Using RATE functionof excel with Nper=79, Pmt=500,PV=-20000, Type=0(End of year payment) | ||||||||||
INVESTMENT A | ||||||||||||
Annual payment at the end of the year | $500 | |||||||||||
Number of payments(N-1) | 80 | |||||||||||
Interest rate | 1.96% | |||||||||||
Present Value of payment | $20,500 | (Using PV functionof excel with RATE=2.05%.Nper=79, Pmt=500,Type=1(Beginning of year payment) | ||||||||||
ANSWER: | ||||||||||||
$20,500 | ||||||||||||
It will be $20,500for any value of N | ||||||||||||
Because in the investment B ,the first payment of $ 500 immeditely is not made. | ||||||||||||
8 | Loan amount | $63,300 | ||||||||||
Annual Interest rate= 15.94%= | 0.1594 | |||||||||||
Special Payment made after 3 years | $7,070 | |||||||||||
Present Value of payment made after 3 years | $ 4,536.49 | (7070/((1+0.1594)^3) | ||||||||||
Balance Loan to be repaid | $58,763.51 | (63300-4536.49) | ||||||||||
Number of payments | 9 | |||||||||||
AnnualPayment X= | $12,729.89 | (Using PMT functionof excel with Rate=0.1594,Nper=9, PV=-58763.51, Type=0(End of year payment) | ||||||||||
Jen's regular annualpayment =X= | $12,729.89 | |||||||||||
9 | Loan amount | $296,538 | ||||||||||
Monthly Interest rate= 0.72%= | 0.0072 | |||||||||||
Special Payment made after 6 months | $32,922 | |||||||||||
Present Value of payment made after 3 years | $ 31,534.93 | 32922/((1+0.0072)^6) | ||||||||||
Balance Loan to be repaid | $265,003.07 | (296538-31534.93) | ||||||||||
Number of payments | 9 | |||||||||||
AnnualPayment X= | $30,296.80 | (Using PMT functionof excel with Rate=0.0072,Nper=9, PV=-265003.07, Type=1(Beginning of month payment) | ||||||||||
Xeviar's regular monthly payment =X= | $30,296.80 | |||||||||||
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