In: Advanced Math
In this question, we are going to call a function, f : R → R, type A, if ∀x ∈ R, ∃y ∈ R such that y ≥ x and |f(y)| ≥ 1. We also say that a function, g, is type B if ∃x ∈ R such that ∀y ∈ R, if y ≥ x, then |f(y)| ≥ 1.
Prove or find a counterexample for the following statements.
(a) If a function is type A, then it is type B.
(b) if a function is type B, then it is type A.