Question

Linux

Given a passed parameter to a script, request a number from the user and print the parameter as many times as that number.

Answer 1

Source Code with comments for your better understanding-

#!/bin/bash
  

#reading the value from the first positional parameter denoted by $1
parameter_read=$1

#readding number from the user
read -p "Please input a number: " numberinput

#printing out the number that was given by the user
echo "You have typed this number ${numberinput}"

#initializing a variable i with digit 1
i=1

#doing a while loop to start from the initialised value of variable i till the digit which was 
#given by the user
while [ "${i}" -le "${numberinput}" ]
do
        #printing out the parameter which was passed in the script
        echo "${parameter_read}"
                #incrementing the variable by adding plus 1
        i=`expr ${i} + 1 `

done

Create a script of your own choice and paste the abovecode in that script

Then call the script in this way (given below) from your command line terminal

sh scriptname parametervalue

where scriptname will be scriptname of your choice and parametervalue will be the parameter name of your choice

In our script I have passed hello as parameter and have given a digit 7 as input

So output will be hello which will be printed 7 times in separate lines

Screenshot-