Question

In: Math

USE SSPS FOR THIS APPLICATION EXERCISE!!! A nurse at a health clinic hypothesizes that ear thermometers...

USE SSPS FOR THIS APPLICATION EXERCISE!!!

A nurse at a health clinic hypothesizes that ear thermometers measure lower body temperature than oral thermometers. The nurse selects a sample of healthy staff members and took the temperature of each with both thermometers. The temperature data are below. What can the nurse conclude with α = 0.05?

ear oral
97.4
98.6
98.9
97.9
99.1
98.2
97.4
97.9
96.3
97.4
98.1
97.7


a) What is the appropriate test statistic?
---Select--- na, z-test, One-Sample t-test, Independent-Samples t-test, Related-Samples t-test

b)
Condition 1:
---Select--- oral thermometer, body temperature, health clinic, staff members, ear thermometer
Condition 2:
---Select--- oral thermometer, body temperature, health clinic, staff members, ear thermometer

c) Compute the appropriate test statistic(s) to make a decision about H0.
(Hint: Make sure to write down the null and alternative hypotheses to help solve the problem.)
p-value =   ; Decision:  ---Select--- Reject H0, Fail to reject H0

d) Using the SPSS results, compute the corresponding effect size(s) and indicate magnitude(s).
If not appropriate, input and/or select "na" below.
d =   ;   ---Select--- na, trivial effect, small effect, medium effect, large effect
r2 =   ;   ---Select--- na, trivial effect, small effect, medium effect, large effect

e) Make an interpretation based on the results. (select one)

-The ear thermometer measured significantly higher temperatures than the oral thermometer.

-The ear thermometer measured significantly lower temperatures than the oral thermometer.    

-There was no significant temperature difference between the ear and oral thermometer.

Solutions

Expert Solution

a) Related-Samples t-test

b)  oral thermometer and ear thermometer

c) NULL HYPOTHESIS H0: d=0

ALTERNATIVE HYPOTHESIS Ha: d <0

d=

test statistic= 2.399

P value= 0.062/2= 0.031

P value is SMALLER than the level of significance 0.05 hence SIGNIFICANT.

Decision: REJECT NULL HYPOTHESIS H0.

d) d= t/sqrt(n)= 2.399/sqrt(6)= 2.399/2.45=0.979  large effect

e) The ear thermometer measured significantly lower temperatures than the oral thermometer


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