In: Statistics and Probability
2. The chair of the Criminal Justice department wants to know if students are generally satisfied with their selection of CJ as a major and if there is a difference in perceptions when students with different educational experiences are compared. She administered a survey to a sample of 100 students, 25 students at each academic rank. Based on the information included in the following table…. [Hint: chi-sq. = 20.49]
Freshman | Sophmore | Junior | Senior | ||
Satisfied | 8 | 15 | 18 | 23 | |
Dissatisfied | 17 | 10 | 7 | 2 | |
Total | 25 | 25 | 25 | 25 | 100 |
2.1. Formulate the null and research/alternative hypotheses.
2.2. Calculate the chi-square
2.3. Report the critical chi-square at the corresponding probability level [.05]and degrees of freedom
2.4. Test the null hypothesis and reach a statistical conclusion
2.5. Interpret your results
2.1) null hypothesis:Ho: satisfaction level of selection of CJ as a major and students with different educational experiences are independent
alternate hypothesis: satisfaction level of selection of CJ as a major and students with different educational experiences are dependent
2.2)
applying chi square test:
Ei=row total*column total/grand total | Freshman | Sophomore | Junior | Senior | Total |
satisfied | 16.00 | 16.00 | 16.00 | 16.00 | 64 |
dissatisfied | 9.00 | 9.00 | 9.00 | 9.00 | 36 |
total | 25 | 25 | 25 | 25 | 100 |
=(Oi-Ei)2/Ei | Freshman | Sophomore | Junior | Senior | Total |
satisfied | 4.0000 | 0.0625 | 0.2500 | 3.0625 | 7.375 |
dissatisfied | 7.1111 | 0.1111 | 0.4444 | 5.4444 | 13.111 |
total | 11.111 | 0.174 | 0.694 | 8.507 | 20.486 |
chi square test statistic =20.486
2.3)
degree of freedom(df) =(rows-1)*(columns-1)= | 3 |
for 3 df and 0.05 level of signifcance critical region χ2= | 7.815 |
2.4)
as test statisitc is higher than critical value we reject null
2.5)
we have sufficient evidence to conclude that satisfaction level of selection of CJ as a major and students with different educational experiences are dependent