A meter stick has a mass of 0.12 kg and balances at its center. When a...

A meter stick has a mass of 0.12 kg and balances at its center. When a small chain is suspended from one end, the balance point moves 29.0 cm toward the end with the chain. Determine the mass of the chain.

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Expert Solution

Initially the balancing point is at center of the meterstick.i.e., at 50 cm point
mass of the meter stick m = 0.12 kg
weight of the stick W = m g
                                = 0.12*9.8 = 1.176 N
After suspended neckalce balancing point is moves 29 cmtoward that end.
So, moment of force of stick = moment of force ofneckalce
                              W* 29 = W ' * ( 50 -29 )
                         1.176* 29 = 21 * W '
from this weight of the necklace   W '= 1.624 N
So, mass of the necklace m ' = W ' / g
                                            = 0.1657 kg
                                            = 165.7 g

genius_generous answered 2 weeks ago

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