Question

In: Physics

The center of gravity of the meter stick is 49 cm. mass of meter stick 50...

The center of gravity of the meter stick is 49 cm. mass of meter stick 50 g . mass of hanger #1 =5 g. mass of hanger #2 = 5 g.

1.Place the fulcrum at 51 cm. Attach a 200 g mass, plus hanger #1, at 17 cm on the meter stick and calculate where to attach a 200 g mass, plus hanger #2, to balance it.

2.Balance the stick with the fulcrum at its center of gravity. Attach a 500 g mass, plus hanger #1, at 32 cm on the meter stick and calculate where to attach a 200 g mass, plus hanger #2, to balance it.

3.Balance the stick with the fulcrum at its center of gravity. Attach a 50 g mass, plus hanger #1, at 8 cm on the meter stick and calculate where to attach a 200 g mass, plus hanger #2, to balance it.

Round to the nearest millimeter. Include units (cm).

Solutions

Expert Solution

Solution:

Given, mass of meter stick = 50 g

Centre of gravity of meter stick is at 49 cm mark.

Mass of hanger #1 = mass of hanger #2 = 5gm

Solution:1

See diagram based on data given in part 1

To balance Hanger #2 and 200gm mass is attached at x cm mark. So net torque of all forces about fulcrum must be zero about any axis.

Net Torque About Fulcrum = 0

(Here Torque in outward direction is written with positive sign, and that in inward direction is written with nigative sign)

205 * 34 + 50 * 2 = 205 * (x - 51)

41 * 34 + 10 * 2 + 41 * 51 = 41 * x

x = 85 + 20/41 cm = 85.5 cm

Solution:2

See diagram based on data given in part 2

To balance Hanger #2 and 200gm mass is attached at x cm mark. So net torque of all forces about fulcrum must be zero about any axis.

Net Torque About Fulcrum = 0

(Here Torque in outward direction is written with positive sign, and that in inward direction is written with nigative sign)

505 * 17  = 205 * (x - 49)

101 * 17 + 41 * 49 = 41 * x

x = 41 + 1717/41 cm = 82.8 cm

Solution:3

See diagram based on data given in part 3

To balance Hanger #2 and 200gm mass is attached at x cm mark. So net torque of all forces about fulcrum must be zero about any axis.

Net Torque About Fulcrum = 0

(Here Torque in outward direction is written with positive sign, and that in inward direction is written with nigative sign)

55 * 41 = 205 * (x - 49)

11 = x - 49

x = 60 cm


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