Question

In: Statistics and Probability

Exercise 8-30 The Appliance Center has six sales representatives at its North Jacksonville outlet. Listed below...

Exercise 8-30

The Appliance Center has six sales representatives at its North Jacksonville outlet. Listed below is the number of refrigerators sold by each last month.

   

Sales Representative Number
Sold
  Zina Craft 54          
  Woon Junge 51          
  Ernie DeBrul 52          
  Jan Niles 47          
  Molly Camp 50          
  Rachel Myak 51          
a. How many samples of size 2 are possible?

     

  No of samples   

    

b.

Select all possible samples of size 2 and compute the mean number sold. (Round Mean values to 1 decimal place.)

     

  Sold   Mean
  (Click to select)54,5254,4754,5150,4747,51   
  (Click to select)54,4750,4754,5247,5154,51   
  (Click to select)47,5154,4754,5154,5250,47   
  (Click to select)47,5154,5154,5250,4754,50   
  (Click to select)54,4747,5152,5150,5154,51   
  (Click to select)47,5150,5151,5254,4754,51     
  (Click to select)54,4747,5150,5154,5151,47   
  (Click to select)52,5154,4751,5054,5147,51   
  (Click to select)54,5151,5147,5152,5154,47   
  (Click to select)47,5152,5154,4752,4754,51   
  (Click to select)47,5152,5052,5154,5154,47   
  (Click to select)50,4754,5152,5147,5154,47   
  (Click to select)47,5054,5254,4747,5154,51   
  (Click to select)47,5154,5254,5154,4751,51   
  (Click to select)54,5154,5254,4747,5150,51   

      

d.

What is the mean of the population? What is the mean of the sample means? (Round your answers to 2 decimal places.)

           

  Mean of sample mean   
  Population mean   

              

f. What is the shape of the distribution of the sample mean?
Uniform
Normal

Solutions

Expert Solution

Answer :

given data :-

we have a tabular form with data

Sales Representative Number
Sold
  Zina Craft 54     
  Woon Junge 51
Ernie DeBrul 52
Jan Niles 47
  Molly Camp 50
  Rachel Myak 51

(a). now we need to find out the  How many samples of size 2 are possible ?

n = 6

r = 2

now we using the combination formula

= n! / r!(n-r)!

= 6! / 2!(6-2)!

= 720 /2(24)

= 720 / 48

= 15

(b).possible samples of size 2 and compute the mean number sold :

54,51 (54+51)/2 = 52.5
54,52 (54+52)/2 = 53
54,47 (54+47)/2 = 49
54,50 (54+50)/2 = 52
54,51

(54+51)/2 = 52.5

51,52 (51+52)/2 = 51.5
51,47 (51+47)/2 = 49
51,50 (51+50)/2 = 50.5
51,51 (51+51)/2 = 51
52,47 (52+47)/2 = 49.5
52,50 (52+50)/2 = 51
52,51 (52+51)/2 = 51.5
47,50 (47+50)/2 =48.5
47,51 (47+51)/2 = 49
50,51 (50+51)/2 = 50.5

(d). the mean of the population and the mean of the sample means :

Mean of sample mean is = (52.5+53+49+52+52.5+51.5+49+50.5+51+49.5+51+51.5+48.5+49+50.5)/15

= 761/15

= 50.73

  Population mean is = (54+51+52+47+50+51)/5

= 305/6

= 50.83

(f).  the shape of the distribution of the sample mean is :

= Normal


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