In: Statistics and Probability
Calculate and interpret 90%, 95%, and 99% confidence intervals for both groups of approaches in question 5. Also provide 90%, 95%, and 99% confidence intervals for both groups when the sample size is increased from 10 to 150. Interpret all statistics. a. A random sample of 15 families representing three social classes has been observed for the frequency with which the parents administer physical punishment to the children over a period of a week. Are the differences significant? Use the five step model as a guide and write a sentence or two of interpretation for your results.
Working |
Middle |
Upper |
Class |
Class |
Class |
10 |
11 |
7 |
9 |
10 |
5 |
4 |
5 |
2 |
2 |
2 |
0 |
1 |
0 |
0 |
b. Three different sections of the same Interstate highway, with roughly equal traffic volumes, have been patrolled by the State Police at different levels of intensity for the past six months. The posted speed limit is 55 and the speeds of a random samples of motorists have been registered for each of the three sections. Is there any statistically significant difference in the speeds? Use the five step model as a guide and write a sentence or two of interpretation for your results.
Lightly |
Moderately |
Heavily |
Patrolled |
Patrolled |
Patrolled |
55 |
57 |
50 |
48 |
58 |
51 |
58 |
58 |
60 |
65 |
55 |
58 |
72 |
55 |
55 |
67 |
59 |
52 |
54 |
58 |
55 |
65 |
54 |
53 |
a) Doing one way anova on the data given follwing is the output:
SUMMARY | ||||||
Groups | Count | Sum | Average | Variance | ||
Working class | 5 | 26 | 5.2 | 16.7 | ||
Middle class | 5 | 28 | 5.6 | 23.3 | ||
Upper class | 5 | 14 | 2.8 | 9.7 | ||
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
Between Groups | 22.93333 | 2 | 11.46667 | 0.692153 | 0.519412 | 3.885294 |
Within Groups | 198.8 | 12 | 16.56667 | |||
Total | 221.7333 | 14 |
Now Let us interpret this anova table:
here p-value is 0.519 and our H0 : means are equal for all the three groups, but since p-value is more than 0.05 we can't reject H0, thus there is no significant difference between the means.
b) Similarly doing one way anova in this case also, the table is:
SUMMARY | ||||||
Groups | Count | Sum | Average | Variance | ||
Lightly patrolled | 8 | 484 | 60.5 | 64.28571 | ||
Moderately patrolled | 8 | 454 | 56.75 | 3.357143 | ||
Heavily patrolled | 8 | 434 | 54.25 | 11.92857 | ||
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
Between Groups | 158.3333 | 2 | 79.16667 | 2.98474 | 0.0723 | 3.4668 |
Within Groups | 557 | 21 | 26.52381 | |||
Total | 715.3333 | 23 |
Here also p-value is more than 0.05 (0.0723), so we cannot reject the H0: that average speed is the same irrespective of patrolling level.
The inital part of question doesn't seem to be related to these parts. Sorry if i missed some part.