Question

In: Statistics and Probability

Calculate and interpret 90%, 95%, and 99% confidence intervals for both groups of approaches in question...

Calculate and interpret 90%, 95%, and 99% confidence intervals for both groups of approaches in question 5. Also provide 90%, 95%, and 99% confidence intervals for both groups when the sample size is increased from 10 to 150. Interpret all statistics. a. A random sample of 15 families representing three social classes has been observed for the frequency with which the parents administer physical punishment to the children over a period of a week. Are the differences significant? Use the five step model as a guide and write a sentence or two of interpretation for your results.

Working

Middle

Upper

Class

Class

Class

10

11

7

9

10

5

4

5

2

2

2

0

1

0

0

b. Three different sections of the same Interstate highway, with roughly equal traffic volumes, have been patrolled by the State Police at different levels of intensity for the past six months. The posted speed limit is 55 and the speeds of a random samples of motorists have been registered for each of the three sections. Is there any statistically significant difference in the speeds? Use the five step model as a guide and write a sentence or two of interpretation for your results.

Lightly

Moderately

Heavily

Patrolled

Patrolled

Patrolled

55

57

50

48

58

51

58

58

60

65

55

58

72

55

55

67

59

52

54

58

55

65

54

53

Solutions

Expert Solution

a) Doing one way anova on the data given follwing is the output:

SUMMARY
Groups Count Sum Average Variance
Working class 5 26 5.2 16.7
Middle class 5 28 5.6 23.3
Upper class 5 14 2.8 9.7
ANOVA
Source of Variation SS df MS F P-value F crit
Between Groups 22.93333 2 11.46667 0.692153 0.519412 3.885294
Within Groups 198.8 12 16.56667
Total 221.7333 14

Now Let us interpret this anova table:

here p-value is 0.519 and our H0 : means are equal for all the three groups, but since p-value is more than 0.05 we can't reject H0, thus there is no significant difference between the means.

b) Similarly doing one way anova in this case also, the table is:

SUMMARY
Groups Count Sum Average Variance
Lightly patrolled 8 484 60.5 64.28571
Moderately patrolled 8 454 56.75 3.357143
Heavily patrolled 8 434 54.25 11.92857
ANOVA
Source of Variation SS df MS F P-value F crit
Between Groups 158.3333 2 79.16667 2.98474 0.0723 3.4668
Within Groups 557 21 26.52381
Total 715.3333 23

Here also p-value is more than 0.05 (0.0723), so we cannot reject the H0: that average speed is the same irrespective of patrolling level.

The inital part of question doesn't seem to be related to these parts. Sorry if i missed some part.


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