In: Statistics and Probability
It is thought that communication mode influences academic, speech, language, and auditory outcomes. To investigate differences in speech production, (GF-Post), the participants were divided into three groups: (1) Those with CIs using listening and spoken language, (2) Those with CIs using total communication, and (3) Those without CIs using total communication.
A) What inferential test should the researchers use to test for differences in speech production at the end of the study?
B)Name the independent and dependent variables and their scales of measurement. Include justification.
Below are summary statistics. Complete the table, parts B and D of the ABCD process, conclude the analysis, and draw warranted conclusions.
GF-Post Means for Communication Groups |
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Group 1 (CI, LSL) |
Group 2 (CI, TC) |
Group 3 (No CI, TC) |
||
Mean |
89.8 |
76.4 |
67.8 |
|
N |
11 |
5 |
16 |
ANOVA Summary Table |
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Source |
df |
MS |
F |
|
Between/Groups |
27.8 |
Fcrit |
||
Within/Error |
8.12 |
Fobt |
C)Do the results require the use of post-hoc tests? Why or why not?
If the results of the analysis of variance require the use of post-hoc tests, employ Fisher’s LSD to determine which groups differ
Given that, Participate devided into following 3 goups of speech production.
1) (CI , LSL) 2) ( CI , TC ) 3) ( No CI , TC )
A)
Here we use ANOVA test for differences in speech production at the end of the study. We calculate F critical value by using formula
And comapire F-Critical value with F-obt, And if F-critical greater than F- obt then we reject Null hypothesis. Where Hypothesis is as follows.
Null Hypothesis : Mean value of all 3 independent goups are equal
Alternative Hypothesis : Mean value of all 3 independent goups are not equal.
And we see below F table for F-obt. value.
B)
Here we check differences between Speech Production , We take a test of 100 marks. So scale of measurement of variables is mark.
here all are independent variables are as
1) CIs using listening and spoken language
2) CIs using total communication
3) without CIs using total communication
From given information we complete the incomplete ANOVA table as
Source | df | MS | F |
Between Group | 3-1 = 2 | 27.8 | |
Within Group | 32 - 3 = 29 | 8.12 | |
Total | 32 - 1 =31 |
From above f table , F-obt = F(2,29 , 0.05) = 3.33
Here, we see that F-Critical > F-obt. So we reject null hypothesis. That we conclude that means of 3 groups are not same.
c) Here means of group are not equal, So we use Post-hoc t-test for cheking which 2 groups are differ.
Where,
We know that MSE is another name for MS Within.
Group | LSD(i , j) | |
(CI , LSL) & ( CI , TC) | 2.8438 | 4.712 |
(CI , LSL) & ( No CI , TC) | 2.0651 | 10.6531 |
(CI , TC) & ( No CI , TC) | 2.7014 | 3.1835 |
And TCritical = T(29 , 0.05) = 1.699 .... For one tail
Here we see that all LSD values of 3 groups combination are greater than 1.699. So we reject null hypothesis.
That is we conclude that, All 3 goups are differ from each other.