In: Chemistry
9 part 6
Calculate the standard cell potential for each of the following electrochemical cells
Part A
Ni2+(aq)+Mg(s)→Ni(s)+Mg2+(aq)
Part B
2H+(aq)+Fe(s)→H2(g)+Fe2+(aq)
Express your answer using two significant figures.
Part C
2NO−3(aq)+8H+(aq)+3Cu(s)→2NO(g)+4H2O(l)+3Cu2+(aq)
Express your answer using two significant figures.
Part A
Mg(s) ---------------> Mg^2+ (aq) + 2e^- E0 = 2.38v
Ni^2+ (aq) + 2e^- -------> Ni(s) E0 = -0.23v
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Ni2+(aq)+Mg(s)---------->Ni(s)+Mg2+(aq) E0cell = 2.15v
Part B
Fe(s) -----------------> Fe^2+ (aq) + 2e^- E0 = 0.41v
2H^+ (aq) + 2e^- ---------> H2(g) E0 = 0.00v
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2H+(aq)+Fe(s)---------->H2(g)+Fe2+(aq) E0cell = 0.41v
Part C
3Cu(s) ---------------------------> 3Cu^2+ (aq) + 6e^- E0 = -0.34v
2NO3^- + 8H^+ (aq) +6e^- -------> 2NO(g) + 4H2O(l) E0 = 0.96v
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2NO3^-(aq)+8H+(aq)+3Cu(s)---->2NO(g)+4H2O(l)+3Cu2+(aq) E0cell = 0.62v